Looking for an AC adaptor
Moderator: Dave Mudgett
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Jim Smith
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- Location: Midlothian, TX, USA
Looking for an AC adaptor
I need some 7-10 VAC 1500 mA adaptors. Not even Radio Shack lists anything with that much amperage. Any ideas where to get them?
I was at a used electronics store and some some that listed the amperage as 20 VA. Does that mean 2000 mA, and would that be too much amperage for my needs?
I was at a used electronics store and some some that listed the amperage as 20 VA. Does that mean 2000 mA, and would that be too much amperage for my needs?
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Jim Smith
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Donny Hinson
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Jim Smith
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Jack Stoner
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I'll have to dig into my books (read the f.... book) and see about the VA rating. I haven't done any of those conversions for years and forgot the formula. I'll check this evening and see if I can find the forumula (unless I get lucky and someone else posts what it is before I get to it). I have to leave in about two hours for my weekly Tuesday (noon) gig.
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Jim Palenscar
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Jim Smith
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Bill Terry
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Jim,
I'm a little rusty on that stuff too
... but here's the way I understand what I read on that link. Power is I*V, which is measured in Watts. So if your device requires 10V at 1500mA, it needs 15 watts.
If your load is purely resistive, (which yours is probably not), then VA = Watts. In that case your 20VA supply = 20Watts and would be fine for a load requiring 15W.
Since your load probably has some reactance, you have to convert the power requirement from Watts to VA. We don't know the actual power factor of your device, so we can use the generic 70% the author recommends. The conversion is:
required VA = required Watts / power factor
VA = 15W /.70
VA required = 21.42
Based on that, looks like the 20VA supply wouldn't provide enough power. Anybody else that REALLY knows this stuff jump right in....
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bterry.home.netcom.com
I'm a little rusty on that stuff too
... but here's the way I understand what I read on that link. Power is I*V, which is measured in Watts. So if your device requires 10V at 1500mA, it needs 15 watts.If your load is purely resistive, (which yours is probably not), then VA = Watts. In that case your 20VA supply = 20Watts and would be fine for a load requiring 15W.
Since your load probably has some reactance, you have to convert the power requirement from Watts to VA. We don't know the actual power factor of your device, so we can use the generic 70% the author recommends. The conversion is:
required VA = required Watts / power factor
VA = 15W /.70
VA required = 21.42
Based on that, looks like the 20VA supply wouldn't provide enough power. Anybody else that REALLY knows this stuff jump right in....
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bterry.home.netcom.com
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Jim Smith
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- Location: Midlothian, TX, USA
Velly intellesting Bill.
Since my unit requires 7-10 VAC @ 1500 mA, if we take the low end of 7 V x 1500 mA = 10.5 watts. Then 10.5/.7 = 15 VA which would be enough. Does that sound right? Guess I need to revisit the store to see exactly how those adaptors are marked and see if the clerks at the second hand electronics store know that much about what they're selling! 
Since my unit requires 7-10 VAC @ 1500 mA, if we take the low end of 7 V x 1500 mA = 10.5 watts. Then 10.5/.7 = 15 VA which would be enough. Does that sound right? Guess I need to revisit the store to see exactly how those adaptors are marked and see if the clerks at the second hand electronics store know that much about what they're selling! 
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Donny Hinson
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Jim, check out this link...
http://www.kingdatron.com/ac.html
They make a lot of power supplies, and I think the table displayed will help you! (1500 ma=1.5amps)
The KWM020-1509 should be what you're looking for...and the reason I'm the only one around is I have no life!
<FONT SIZE=1 COLOR="#8e236b"><p align=CENTER>[This message was edited by Donny Hinson on 19 December 2000 at 05:31 PM.]</p></FONT>
http://www.kingdatron.com/ac.html
They make a lot of power supplies, and I think the table displayed will help you! (1500 ma=1.5amps)
The KWM020-1509 should be what you're looking for...and the reason I'm the only one around is I have no life!
<FONT SIZE=1 COLOR="#8e236b"><p align=CENTER>[This message was edited by Donny Hinson on 19 December 2000 at 05:31 PM.]</p></FONT>-
Jim Smith
- Posts: 7949
- Joined: 4 Aug 1998 11:00 pm
- Location: Midlothian, TX, USA
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Donny Hinson
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- Location: Glen Burnie, Md. U.S.A.

