Mosvalve 500 - Power supply???

Dag Wolf · Post by **Dag Wolf** » 15 May 2000 6:47 am

Can someone tell me how much watts a mosvalve 500 consume from the power outlet? I need to know how many watts my new power supply will have to be. I`m changing from 110volts to 220volts.

Thanks,Dag

Jack Stoner · Post by **Jack Stoner** » 15 May 2000 6:55 am

My MosValve 500 has listed on the back panel, 120VAC 1400 watts, 12Amp fuse.

I would say you need something that will provide, at a minimum, 120VAC at 12 amps.

Dag Wolf · Post by **Dag Wolf** » 15 May 2000 2:41 pm

Jack, thanks a lot. I guess the 1400 watts is the info I was looking for.

Thanks again, Dag

Rich Paton · Post by **Rich Paton** » 22 May 2000 4:24 pm

Dag, at 220 VAC, producing 1400 watts would require 6.36 Amperes maximum load on the mains circuit.
This "maximum power consumed" condition would only exist with the amp at full tilt, on a sine-wave test signal, output unclipped.
I'll bet that would be LOUD![This message was edited by Rich Paton on 22 May 2000 at 05:29 PM.][This message was edited by Rich Paton on 22 May 2000 at 09:46 PM.]

Dag Wolf · Post by **Dag Wolf** » 22 May 2000 5:18 pm

Hey Thanks Rich, I didn`t know that bringing it from 110volt to 220volt make the watt consum lower. If I`m wrong please fill me in.

Thanks, Dag

Rich Paton · Post by **Rich Paton** » 22 May 2000 8:44 pm

Dag, the consumed power (actually called Volt-Amperes because of the transformer's inductive qualities) is a function of the voltage (E) multiplied by the current (I).
BTW, watts of electrical exist power only exist in a restive load such as an incandescent lamp or resistive heating element.
Anyway, back to the 220 Volt issue,
we'll call it watts for now...
1400 "Watts" equals 220 volts X 6.36 amps,
by using one of the formulas:
P = I x E (power equals Current "I" times Volts "E",
P = I squared X R (power equals the current squared times the load resistance "R"),
or P = E squared / R (power equals the voltage "E" squared, divided by the load resistance "R"

Since we know the power and voltage, use
1400 "watts" divided by 220 Volts. The answer would be 1400/220 = 6.36 Amps.

Dag Wolf · Post by **Dag Wolf** » 23 May 2000 3:27 pm

I guess I should have paid better attention at school.

Thanks Rich,
Dag